F 1, which is the force used to the cork split by the area that the cork and also that's walking to equal the force applied to the bottom of the jug, F 2, split by the area that the bottom the the jug, A 2. Therefore we desire to recognize what F 2 is and so we'll main point both sides by A 2 to fix for it climate switch the political parties around. So F 2 is F 1 times A 2 end A 1; the area of the bottom the the jug will certainly be π times the radius of the circular bottom squared and also the radius is fifty percent the diameter and also then exact same for the A 1—same formula— yet d 1 instead of d 2. The π's cancel and also so execute these denominators which will come to be 4 after girlfriend square the denominators; castle cancel and we are left v F 1d 2 squared end d 1 squared. For this reason that's 120 newtons applied times 14.0 time 10 to the minus 2 meters— diameter of the bottom the the jug—squared split by 2.00 times 10 come the minus 2 meters—for the cork—squared and also that's 5880 newtons. And to find the extra force, us take 120 newtons away from that and this is the amount through which the pressure on the bottom of the jug above the force applied and that's 5760 newtons.">

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This is college Physics Answers with Shaun Dychko. A cork is pounded right into the height of a jug that wine v a force of 120 newtons and also the diameter that the cork is 2.00 centimeters and the diameter the the bottom that the jug is 14.0 centimeters and this bottom mister off and we are meant to calculate just how much force beyond the 120 newtons applied is top top the bottom of the jug? for this reason we convert these centimeters into meters return it turns out that"s no really necessary because we are just dividing the squares of these numbers and so it just matters the the units are the same but I did it the end of a matter of habit. Therefore we know that the push where the cork is will certainly be very same as the press at the bottom that the jug and also I have written pressure as force divided by area here. For this reason this is the F 1, i m sorry is the force used to the cork separated by the area of the cork and that"s going to same the force used to the bottom the the jug, F 2, divided by the area the the bottom that the jug, A 2. So we want to recognize what F 2 is and so we"ll multiply both political parties by A 2 to settle for it then switch the political parties around. So F 2 is F 1 times A 2 end A 1; the area of the bottom that the jug will be π times the radius of the circular bottom squared and also the radius is fifty percent the diameter and then exact same for the A 1—same formula— but d 1 rather of d 2. The π"s cancel and also so perform these platform which will end up being 4 after girlfriend square the denominators; castle cancel and also we space left v F 1d 2 squared over d 1 squared. For this reason that"s 120 newtons applied times 14.0 time 10 come the minus 2 meters— diameter of the bottom that the jug—squared split by 2.00 times 10 come the minus 2 meters—for the cork—squared and that"s 5880 newtons. And to discover the extra force, we take 120 newtons far from that and also this is the amount by which the force on the bottom the the jug over the force applied and also that"s 5760 newtons.
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